有关QWidget::render() [复制链接]

各位老大，文档中对QWidget::redner(QPaintDevice* target, ....)的解释是将target 渲染到当前的QWidget上，可是在QT提供的例子中，有这样一段代码(在一个QWidget中）：
        QPixmap pixmap1(size());
                  render(&pixmap);
最终结果好象是将当前QWidget的pixmap渲染了pixmap1。不知具体是怎么回事

文档中对QWidget::redner(QPaintDevice* target, ....)的解释是将target 渲染到当前的QWidget上?
仔细理解target的含义

你看错了
void QWidget::render ( QPaintDevice * target, const QPoint & targetOffset = QPoint(), const QRegion & sourceRegion = QRegion(), RenderFlags renderFlags = RenderFlags( DrawWindowBackground | DrawChildren ) )
Renders the sourceRegion of this widget into the target using renderFlags to determine how to render. Rendering starts at targetOffset in the target. For example:
QPixmap pixmap(widget->size());
widget->render(&pixmap);If sourceRegion is a null region, this function will use QWidget::rect() as the region, i.e. the entire widget.

Note: Make sure to call QPainter::end() for the given target's active painter (if any) before rendering. For example:

QPainter painter(this);
...
painter.end();
myWidget->render(this);This function was introduced in Qt 4.3.