如何获取当前屏幕分辨率宽度？ [复制链接]

我在程序中 如何方便的获取当前显示的分辨率？
有没有int window.width() 之类的方法？

回答的真够手把手了

QApplication::desktop()->availableGeometry
    Returns the available geometry of the screen with index screen. What is available will be subrect of screenGeometry() based on what the platform decides is available (for example excludes the dock and menu bar on Mac OS X, or the task bar on Windows).
QApplication::desktop()->screenGeometry
    Returns the geometry of the screen with index screen.

thanks

error: cannot call member function ‘const QRect QDesktopWidget::screenGeometry(int) const’ without object

已经说的很明确了，要访member function QDesktopWidget::screenGemetry，必须先创建类的 object

class WebCross : public QWidget
QWidget有没有获取屏幕分辨率的方法

引用第3楼tsuibin于2009-11-11 16:53发表的  :
error: cannot call member function ‘const QRect QDesktopWidget::screenGeometry(int) const’ without object

翻译成中文就是你要的答案了。

题外，有时间多看看C++吧

error: cannot call member function ‘const QRect QDesktopWidget::screenGeometry(int) const’ without object

学习ing

QDesktopWidget * QApplication::desktop ()   [static]

const QRect QDesktopWidget::screenGeometry ( int screen = -1 ) const
Returns the geometry of the screen with index screen. The default screen is used if screen is -1.
See also screenNumber().

int QRect::width () const
int QRect::height () const