QT中静态函数无法直接用emit发出信号,那请问有什么方法可以发一个信号呢? - QTCN开发网

离线kinzess

新手上路

只看楼主倒序阅读楼主发表于: 2010-02-16

rt...那个static函数,无法改造成普通函数,需要在里面发出一个信号,
但是如果这样,emit又无法使用,那要如何发出一个信号呢?

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离线steinlee

侠客

只看该作者 1楼发表于: 2010-02-17

inside a static function you can call only static functions. Emitting a signal is not a static function call.
Therefore, it will not work. You need to work around this. You can change this func to be nonstatic.

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离线kinzess

新手上路

只看该作者 2楼发表于: 2010-02-17

引用第1楼steinlee于2010-02-17 01:14发表的 :
inside a static function you can call only static functions. Emitting a signal is not a static function call.
Therefore, it will not work. You need to work around this. You can change this func to be nonstatic.

那静态函数我就是没办法更改,所以才如此头痛......

离线yj_yulin

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只看该作者 3楼发表于: 2010-02-17

postevent然后在事件处理里面emit

离线steinlee

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只看该作者 4楼发表于: 2010-02-18

Use this static function to change a static variable. emit your signal just after this static func call according to the change of this static variable.