QRegExp类中"\\s+"看不太明白？ [复制链接]

在 QRegExp 类中写到:
QRegExp rx( "^\\S+$" );   // match strings without whitespace就是与没有空格的匹配吧。
在QString类中提到：
QString line( "forename\tmiddlename surname \t \t phone" );
QRegExp sep( "\s+" );
QString s = line.section( sep, 2, 2 ); // s == "surname"我能理解

如果start或者end为负数，我们就从字符串的右面开始计数，最右面的是-1，接着是-2，依此类推。

QString line( "forename\tmiddlename surname \t \t phone" );
QRegExp sep( "\\s+" );
QString s = line.section( sep, -3, -2 ); // s == "middlename surname"我不太明白？

4 comments:

1. (From http://doc.trolltech.com/4.1/qregexp.html): Note: The C++ compiler transforms backslashes in strings, so to include a \ in a regexp, you will need to enter it twice, i.e. \\. To match the backslash character itself, you will need four: \\\\.
2. \S and \s are different
3. " \t \t " is multiple white spaces, i.e., matched by ONE "\\s+"
4. You probably neglected "+" in "\\s+" and were thinking about "\\s"?

Thank you very much!
QRegExp sep( "\s+" ); means what? I am in a puzzle here.
QRegExp sep( "\\s+" ); means one more whitespace

正则表达式啦~
\是特殊字符 所以需要转译\\
\s是空格span