[提问]qt 写的 多个正六边形的坐标怎么转换为数组下标 [复制链接]

qt 写的 多个正六边形的坐标怎么转换为数组下标

举个例子？

是的 四边形的很好写 六边形的我不知道怎么弄了 谢谢

发代码给我看也行

完全没理解什么意思……

图片:3.png

在正六边形里 event->x()  event->y()   转换为数组下标

#define SIZE 12.5
#define HOR 21
#define VER 13

for(int j=0;j<=VER;j++)
    {
        if(j % 2 ==0)
        {
            for(int i =1 ; i <= HOR;i++)
            {
                QPointF points[6];
                points[0]=QPointF(2*SIZE*i,j*3*SIZE*qSqrt(3)/3);
                points[1]=QPointF(SIZE*(2*i+1),(j*3+1)*SIZE*qSqrt(3)/3);
                points[2]=QPointF(SIZE*(2*i+1),(j+1)*3*SIZE*qSqrt(3)/3);
                points[3]=QPointF(2*SIZE*i,((j+1)*3+1)*SIZE*qSqrt(3)/3);
                points[4]=QPointF(SIZE*(2*i-1),(j+1)*3*SIZE*qSqrt(3)/3);
                points[5]=QPointF(SIZE*(2*i-1),(j*3+1)*SIZE*qSqrt(3)/3);

                painter.drawPolygon(points,6);

            }
        }
        else
        {
            for(int i =1 ; i <= HOR;i++)
            {
                QPointF points[6];
                points[0]=QPointF((2*i-1)*SIZE, j*3*SIZE*qSqrt(3)/3);
                points[1]=QPointF(SIZE*2*i,(j*3+1)*SIZE*qSqrt(3)/3);
                points[2]=QPointF(SIZE*2*i,(j+1)*3*SIZE*qSqrt(3)/3);
                points[3]=QPointF((2*i-1)*SIZE,((j+1)*3+1)*SIZE*qSqrt(3)/3);
                points[4]=QPointF(SIZE*(2*i-2),(j+1)*3*SIZE*qSqrt(3)/3);
                points[5]=QPointF(SIZE*(2*i-2),(j*3+1)*SIZE*qSqrt(3)/3);

                painter.drawPolygon(points,6);

            }
        }
    }
画六边形

那就看你的数学功底了，这个应该是得计算的吧