运行单一程序 [复制链接]

单一进程测试函数：
bool JasonQt_SingleApplication(const QString &flag){    static QSharedMemory *shareMem = NULL;
    if(shareMem)    {        return true;    }
    shareMem = new QSharedMemory("JasonQt_SingleApplication_Control_" + flag);
    volatile short i = 2;    while (i--)    {        if (shareMem->attach(QSharedMemory::ReadOnly))        {            shareMem->detach();        }    }
    if(shareMem->create(1))    {        return true;    }
    return false;}



单一进程在main函数中的使用
int main(int argc, char *argv[]){    QApplication a(argc, argv);     SystemTrayIcon w;

    w.show();
    if(!JasonQt_SingleApplication("w"))    {        qDebug("No Single!");        return -1;
    }    return a.exec();}






if(!JasonQt_SingleApplication("w")) {     qDebug("No Single!");     return -1;
}

有一问题想请教楼主，程序异常退出后，下次再重新启动应用，该如何处理？