书里面的第四里例子，前面几个都能很成功的运行，但这个却出现了错误，很郁闷，希望大家能帮助解决
代码如下：
#include <QtGui>
#include "finddialog.h"
FindDialog::FindDialog(QWidget *parent) : QDialog(parent)
{
label = new QLabel(tr("Find &what:"));
lineEdit = new QLineEdit;
label->setBuddy(lineEdit);
caseCheckBox = new QCheckBox(tr("Match &case"));
backwardCheckBox = new QCheckBox(tr("Search &backward"));
findButton= new QPushButton(tr("&Find"));
findButton->setDefault(true);
findButton->setEnabled(false);
closeButton = new QPushButton(tr("close"));
connect(lineEdit,SIGNAL(textChanged(const QString &)),this,SLOT(enableFindButton(const QString &)));
connect(findButton,SIGNAL(clicked()),this,SLOT(findClicked()));
connect(closeButton,SIGNAL(clicked()),this,SLOT(close()));
QHBoxLayout *topLeftLayout = new QHBoxLayout;
topLeftLayout->addWidget(label);
topLeftLayout->addWidget(lineEdit);
QVBoxLayout *leftLayout = new QVBoxLayout;
leftLayout->addLayout(topLeftLayout);
leftLayout->addWidget(caseCheckBox);
leftLayout->addWidget(backwardCheckBox);
QVBoxLayout *rightLayout = new QVBoxLayout;
rightLayout->addWidget(findButton);
rightLayout->addWidget(closeButton);
rightLayout->addStretch();
QHBoxLayout *mainLayout = new QHBoxLayout;
mainLayout->addLayout(leftLayout);
mainLayout->addLayout(rightLayout);
setLayout(mainLayout);
setWindowTitle(tr("Find"));
setFixedHeight(sizeHint().height());
}
void FindDialog::findClicked()
{
QString text = lineEdit->text();
Qt::CaseSensitivity cs = caseCheckBox->isChecked()?Qt::CaseSensitive:Qt::CaseInsensitive;
if(backwardCheckBox->isChecked())
{
emit findPrevious(text,cs);
}
else
{
emit findNext(text,cs);
}
}
void FindDialog::enableFindButton(const QString &text)
{
findButton->setEnabled(!text.isEmpty());
}
调试信息如下：
4 E:\Dev-Cpp\Project\Ex4\finddialog.cpp new types may not be defined in a return type
4 E:\Dev-Cpp\Project\Ex4\finddialog.cpp return type specification for constructor invalid
E:\Dev-Cpp\Project\Ex4\Makefile.win [Build Error] [finddialog.o] Error 1
我就很奇怪，为什么会出现这样的情况，调试信息看得懂，但解决不了
