以下情况如何创建数据库表？ [复制链接]

    我的表名开始没有确定，而是通过一个字符串确定，如下：
    QString tab="mytab";
    QSqlQuery query;
    query.exec("CREATE TABLE  表名 (id INTEGER PRIMARY KEY AUTOINCREMENT,"//这里要求表名=tab字符串
                                                   "datetime  VARCHAR(30) ,"
                                                   "name VARCHAR(30) ,"
                                                   "addr VARCHAR(16),"
                                                   "type VARCHAR(20) ,"
                                                   "explain VARCHAR(10) )");

摸索了老半天终于找到了一个好的方法，呵呵，自己动手丰衣足食。
QString aaa="messageofalarm_fault";
query.exec(QString("CREATE TABLE %1(id INTEGER PRIMARY KEY AUTOINCREMENT,"
                                                   "datetime  VARCHAR(30) ,"
                                                   "name VARCHAR(30) ,"
                                                   "addr VARCHAR(16),"
                                                   "type VARCHAR(20) ,"
                                                   "explain6VARCHAR(10) )").arg(aaa));