在上面的帖子中,我已经找到了一个通融的方法,虽然这样可能不友好。
#include <QGuiApplication>
#include <QQmlApplicationEngine>
#include <QtPlugin>
#include <QtQml>
#if defined(QT_STATIC) && !defined(Q_OS_MAC) && !defined(QT_NAMESPACE)
Q_IMPORT_PLUGIN(QtQuick2Plugin)
Q_IMPORT_PLUGIN(QtQuickControlsPlugin)
Q_IMPORT_PLUGIN(QtQuickLayoutsPlugin)
Q_IMPORT_PLUGIN(QtQuick2WindowPlugin)
#endif
int main( int argc, char* argv[] )
{
QGuiApplication app( argc, argv );
……
QQmlApplicationEngine engine;
// 在静态编译下一个通融的解决方法是显式地注册QML类
#if defined(QT_STATIC) && !defined(Q_OS_MAC) && !defined(QT_NAMESPACE)
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuick2Plugin().instance()) ->registerTypes("QtQuick");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuickControlsPlugin().instance())->registerTypes("QtQuick.Controls");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuickControlsPlugin().instance())->registerTypes("QtQuick.Controls.Private");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuickControlsPlugin().instance())->registerTypes("QtQuick.Controls.Styles");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuickLayoutsPlugin().instance()) ->registerTypes("QtQuick.Layouts");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuick2WindowPlugin().instance()) ->registerTypes("QtQuick.Window.2");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuick2Plugin().instance()) ->initializeEngine( &engine, "QtQuick");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuickControlsPlugin().instance())->initializeEngine( &engine, "QtQuick.Controls");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuickLayoutsPlugin().instance()) ->initializeEngine( &engine, "QtQuick.Layouts");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuickLayoutsPlugin().instance()) ->initializeEngine( &engine, "QtQuick.Layouts");
qobject_cast<QQmlExtensionPlugin*>(qt_static_plugin_QtQuick2WindowPlugin().instance()) ->initializeEngine( &engine, "QtQuick.Window.2");
#endif
……
return app.exec( );
}