[讨论]QTcpSocket客户端问题 [复制链接]

QTcpSocket 这不是坑爹吗，我电脑上分配了多个IP，采用QTcpSocket编写的客户端，先绑定了指定IP地址，然后连接。绑定之后，我还打印了localAddress和localPort，结果他连接的时候就变成了另外一个地址，而且不管我怎么绑定，到服务器之后地址永远都不变，然后我用原生的socket操作，socket -- bind -- connect，到服务器那边获取的IP地址就是我客户端绑定的地址，屡试不爽，难道这是一个bug。

最后我很想知道为什么，查看qt的源代码，在connectToHost函数中发现，在连接之前qt把localAddress给clear了，难道客户端就不能绑定IP吗。这是哪门子的事啊，然后我在connectToHost之后再打印localAddress，确实为空。整了好久，以为是我的电脑IP没有分配好，原来是QT在里面干坏事。

void QAbstractSocket::connectToHost(const QString &hostName, quint16 port,
                                    OpenMode openMode,
                                    NetworkLayerProtocol protocol)
{
    Q_D(QAbstractSocket);
#if defined(QABSTRACTSOCKET_DEBUG)
    qDebug("QAbstractSocket::connectToHost(\"%s\", %i, %i)...", qPrintable(hostName), port,
           (int) openMode);
#endif

    if (d->state == ConnectedState || d->state == ConnectingState
        || d->state == ClosingState || d->state == HostLookupState) {
        qWarning("QAbstractSocket::connectToHost() called when already looking up or connecting/connected to \"%s\"", qPrintable(hostName));
        d->socketError = QAbstractSocket::OperationError;
        setErrorString(QAbstractSocket::tr("Trying to connect while connection is in progress"));
        emit error(d->socketError);
        return;
    }

    d->preferredNetworkLayerProtocol = protocol;
    d->hostName = hostName;
    d->port = port;
    d->state = UnconnectedState;
    d->buffer.clear();
    d->writeBuffer.clear();
    d->abortCalled = false;
    d->closeCalled = false;
    d->pendingClose = false;
    d->localPort = 0;
    d->peerPort = 0;
    d->localAddress.clear();
    d->peerAddress.clear();
    d->peerName = hostName;
    if (d->hostLookupId != -1) {
        QHostInfo::abortHostLookup(d->hostLookupId);
        d->hostLookupId = -1;
    }
......
......
}